The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm {d}x$ in elementary …

Feb 17, 2025 · The noun phrase "improper integral" written as $$ \int_a^\infty f (x) \, dx $$ is well defined. If the appropriate limit exists, we attach the property "convergent" to that expression …

@user599310, I am going to attempt some pseudo math to show it: $$ I^2 = \int e^-x^2 dx \times \int e^-x^2 dx = Area \times Area = Area^2$$ We can replace one x, with a dummy variable, …

Jan 7, 2026 · A closed form for an integral involving arcsin and a square-root Ask Question Asked 12 days ago Modified 11 days ago

Feb 6, 2026 · Evaluate an integral involving a series and product in the denominator Ask Question Asked 3 days ago Modified 2 days ago

Feb 4, 2018 · The integral of 0 is C, because the derivative of C is zero. Also, it makes sense logically if you recall the fact that the derivative of the function is the function's slope, because …

Oct 11, 2025 · However, one "intrinsic integral closure" that is often used is the normalization, which in the case on an integral domain is the integral closure in its field of fractions. It's the …

Aug 18, 2020 · Why is $\\displaystyle \\int \\dfrac{dy}{dx} dx = y + c$, but for example $\\displaystyle \\int \\dfrac{dy}{dx} y dx = \\dfrac{1}{2} y^2 + c$ instead of $\\dfrac{1}{2 ...

Dec 15, 2017 · A different type of integral, if you want to call it an integral, is a "path integral". These are actually defined by a "normal" integral (such as a Riemann integral), but path …

If by integral you mean the cumulative distribution function $\Phi (x)$ mentioned in the comments by the OP, then your assertion is incorrect.